HoDoKu Solving Technique Index: Example for "Forcing Net Verity (only net 3)"
Original sudoku:
..........3..7.8.98....315.9.8142............5..6...4.1.42........7....6.8...531.
Use the following line if you want to load the sudoku in HoDoKu:
:1204::...+8......3+1+57.8.98....315.9.8142......+3+5....5.+36...4.1.42+3....+3..7....6.8...531.:211 412 612 712 213 613 713 416 916 933 572 982 986 587 987::
The following representation can be pasted in most Sudoku programs:
.-------------------.---------------.-------------------. | 467 259 59 | 8 1269 16 | 2467 2367 2347 | | 246 3 1 | 5 7 46 | 8 26 9 | | 8 24679 267 | 49 269 3 | 1 5 247 | :-------------------+---------------+-------------------: | 9 67 8 | 1 4 2 | 567 367 357 | | 2467 12467 267 | 3 5 789 | 2679 26789 1278 | | 5 127 3 | 6 89 789 | 279 4 1278 | :-------------------+---------------+-------------------: | 1 679 4 | 2 3 689 | 579 789 578 | | 3 25 259 | 7 189 148 | 24 289 6 | | 267 8 2679 | 49 69 5 | 3 1 247 | '-------------------'---------------'-------------------'
Representation of the step:
.----------------------.------------------.----------------------. | *467 *259 *59 | 8 1269 *16 | *2467 *2367 2347 | | *246 3 1 | 5 7 *46 | 8 *26 9 | | 8 *24679 *267 | *49 *269 3 | 1 5 *247 | :----------------------+------------------+----------------------: | 9 *67 8 | 1 4 2 | 567 367 357 | | 2467 *12467 *267 | 3 5 789 | 2679 26789 *1278 | | 5 127 3 | 6 *89 789 | 279 4 *1278 | :----------------------+------------------+----------------------: | 1 *679 4 | 2 3 *689 | *579 *789 *578 | | 3 *25 *259 | 7 *189 *148 | *24 *289 6 | | *267 8 *2679 | *49 *69 5 | 3 1 *247 | '----------------------'------------------'----------------------' Forcing Net Verity => r1c2=5 r7c2=6 (r4c2=7 r5c3<>7) (r3c2<>6) r9c5=6 (r9c5<>9) (r9c5<>9) r3c3=6 (r5c3=2 r8c3<>2) (r1c1=7 r9c1=2 r8c2=5 r8c3=9 r8c8=8 r7c9<>8) r9c3=7 r9c4=9 r3c4=4 r5c2=4 r5c9=1 r6c9=8 r8c5=8 r8c6=1 r1c6=6 r2c6=4 r3c4=9 r9c3=9 r8c3=5 r1c2=5 r7c2=7 (r7c2<>6) (r4c2=6 r3c2<>6) (r7c8<>7) (r7c7<>7) r9c9=7 (r3c3=7 r9c3=6 r9c1<>6) (r3c3=7 r3c3<>6) (r9c9<>2) r8c7=4 r8c8=2 r2c8=6 (r1c7<>6) r1c1=6 r2c8=6 (r1c7<>6) r2c1=2 r9c1=7 r7c2=9 (r1c2<>9) r1c3=9 r1c2=5 r7c2=9 (r1c2<>9) r1c3=9 r1c2=5
Copyright © 2008-12 by Bernhard Hobiger
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